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y^2+875-60y=0
a = 1; b = -60; c = +875;
Δ = b2-4ac
Δ = -602-4·1·875
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-10}{2*1}=\frac{50}{2} =25 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+10}{2*1}=\frac{70}{2} =35 $
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